$BI=(B 5.19:
$BBPHf3S2A$7$?Nc(B($BF|1QK]Lu$N=EJ8J#J8(B)
=0.3cm
|
$B$$$:$l$NK]Lu7k2L$K$*$$$F$bDs0F
$BI=(B 5.20:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$NC1J8(B)
=0.8cm
|
$B$$$:$l$NK]Lu7k2L$K$*$$$F$bDs0F
$BI=(B 5.21:
$BBPHf3S2A$7$?Nc(B($B1QF|K]Lu$N=EJ8J#J8(B)
=1.7cm
|
$B$$$:$l$NK]Lu7k2L$K$*$$$F$bDs0F
$BJ?@.(B21$BG/(B3$B7n(B17$BF|(B